Changes

map in the input sequence <code>$inputmaps</code> that contains an

The expression <code>map:new()</code> returns <code>map{}</code>. <em>(Returns an empty map, whose collation is the default collation from the static context).</em><br/>The expression <code>map:new(())</code> returns <code>map{}</code>. <em>(Returns an empty map, whose collation is the default collation from the static context).</em><br/>The expression <code>map:new(map:entry(0, "no"), map:entry(1, "yes"))</code> returns <code>map{0:="no", 1:="yes"}</code>. <em>(Returns a map with two entries; the collation of the map is the default collation from the static context).</em><br/>The expression <code>map:new(map:entry(0, "no"), map:entry(1, "yes"))</code> returns <code>map{0:="no", 1:="yes"}</code>. <em>(Returns a map with two entries; the collation of the map is the default collation from the static context).</em><br/>The expression <code>map:new(($week, map{7:="Unbekannt"}))</code> returns <code>map{0:="Sonntag", 1:="Montag", 2:="Dienstag", 3:="Mittwoch", 4:="Donnerstag", 5:="Freitag", 6:="Samstag", 7:="Unbekannt"}</code>. <em>(The value of the existing map is unchanged; a new map is created containing all the entries from <code>$week</code>, supplemented with a new entry.).</em><br/>The expression <code>map:new(($week, map{6:="Sonnabend"}))</code> returns <code>map{0:="Sonntag", 1:="Montag", 2:="Dienstag", 3:="Mittwoch", 4:="Donnerstag", 5:="Freitag", 6:="Sonnabend"}</code>. <em>(The value of the existing map is unchanged; a new map is created containing all the entries from <code>$week</code>, with one entry replaced by a new entry. Both input maps contain an entry with the key value <code>6</code>; the one used in the result is the one that comes last in the input sequence.).</em><br/>The expression <code>map:new((map{"A":=1}, map{"a:=2"}), "http://collation.example.com/caseblind")</code> returns <code>map{"a":=2}</code>. <em>(Assuming that the keys of the two entries are equal under the rules of the chosen collation, only one of the entries can appear in the result; the one that is chosen is the one from the last map in the input sequence. If both entries were in the same map, it would be implementation-dependent which was chosen.).</em><br/>